The length of second's hand in watch is 1 | vedclass

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Question

(d) $\Delta v = 2v\sin \left( {\frac{{90^\circ }}{2}} ight) = 2v\sin 45^\circ $

$ = 2v 	imes \frac{1}{{\sqrt 2 }} = \sqrt 2 v$

$ = \sqrt 2

Vedclass · Accepted Answer

$\frac{{\pi \sqrt 2 }}{{30}}\,\,cm/\sec $

Vedclass · Answer

(d) $\Delta v = 2v\sin \left( {\frac{{90^\circ }}{2}} ight) = 2v\sin 45^\circ $

$ = 2v 	imes \frac{1}{{\sqrt 2 }} = \sqrt 2 v$

$ = \sqrt 2 	imes r\omega = \sqrt 2 	imes 1 	imes \frac{{2\pi }}{{60}} = \frac{{\sqrt 2 \pi }}{{`30}}\;cm/s$

The length of second's hand in watch is $1 \,cm.$ The change in velocity of its tip in $15$ seconds is

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