A body starts from rest from the origin with | vedclass

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Question

$x = {u_x}t + \frac{1}{2}{a_x}{t^2} = \frac{1}{2} 	imes 6 	imes {(4)^2} = 48\,m$

$y = {u_y}t + \frac{1}{2}{a_y}{t^2} = \frac{1}{2} 	imes 8 	ime

Vedclass · Accepted Answer

$80$

Vedclass · Answer

$x = {u_x}t + \frac{1}{2}{a_x}{t^2} = \frac{1}{2} 	imes 6 	imes {(4)^2} = 48\,m$

$y = {u_y}t + \frac{1}{2}{a_y}{t^2} = \frac{1}{2} 	imes 8 	imes {(4)^2} = 64\,m$

$d = \sqrt {{x^2} + {y^2}} = \sqrt {{{(48)}^2} + {{(64)}^2}} = 80\,m$

A body starts from rest from the origin with an acceleration of $6 \;m / s^2$ along the $x$-axis and $8\; m / s^2$ along the $y$-axis. Its distance from the origin after $4\; seconds$ will be

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