The ionic radius of Cr is minimum is which of | vedclass

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Question

The oxidation state of $Cr$ in different compounds are

$CrCl _3 \ldots+3$

$CrF _3 \quad \ldots+3$

$Cr _2 O _3 \cdots+3$

$K _2 CrO _4 \quad

Vedclass · Accepted Answer

$K_2CrO_4$

Vedclass · Answer

The oxidation state of $Cr$ in different compounds are

$CrCl _3 \ldots+3$

$CrF _3 \quad \ldots+3$

$Cr _2 O _3 \cdots+3$

$K _2 CrO _4 \quad \cdots+6$

As oxidation state of $Cr$ is maximum (maximum positive charge) in $K _2 CrO _4$ so ionic radii of $Cr$ is minimum here.

The ionic radius of $Cr$ is minimum is which of the following compounds

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