All $Zn( +II)$ compounds are white because

  • A

    $Zn^{2+}$ has a $d^{10}$ configuration and the $d-$ subshell is full

  • B

    $Zn^{2+}$ shows $d-d$ transition

  • C

    $Zn^{2+}$ has no electron in the $4s-$ subshell

  • D

    $Zn$ is not a transition element

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