All $Zn( +II)$ compounds are white because

  • A

    $Zn^{2+}$ has a $d^{10}$ configuration and the $d-$ subshell is full

  • B

    $Zn^{2+}$ shows $d-d$ transition

  • C

    $Zn^{2+}$ has no electron in the $4s-$ subshell

  • D

    $Zn$ is not a transition element

Similar Questions

Predict which of the following will be coloured in aqueous solution? $Ti ^{3+}, V ^{3+}, Cu ^{+},$ $Sc ^{3+}, Mn ^{2+}, Fe ^{3+}$ and $Co ^{2+} .$ Give reasons for each. 

Given below are two statements, one is labelled as Assertion $A$ and the other is labelled as Reason $R$.

Assertion $A:$ The spin only magnetic moment value for $\left[ Fe ( CN )_6\right]^{3-}$ is $1.74 BM$, whereas for $\left[ Fe \left( H _2 O \right)_6\right]^{3+}$ is $5.92\,BM$.

Reason $R :$ In both complexes, $Fe$ is present in +3 oxidation state.

In the light of the above statements, choose the correct answer from the options given below:

  • [JEE MAIN 2023]

Which of the following compounds is not colored yellow ?

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Explain trends in $M^{2+}/M$ standard electrode potentials.

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