The function f(x) = ax + b is strictly increa | vedclass

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(A) function $f(x)$ is strictly increasing if its derivative $f'(x) > 0$ for all $x$ in its domain.Given the function $f(x) = ax + b$.Taking the deriv

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$a > 0$

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(A) function $f(x)$ is strictly increasing if its derivative $f'(x) > 0$ for all $x$ in its domain.Given the function $f(x) = ax + b$.Taking the derivative with respect to $x$,we get $f'(x) = \frac{d}{dx}(ax + b) = a$.For the function to be strictly increasing,we must have $f'(x) > 0$.Substituting the derivative,we get $a > 0$.Therefore,the function is strictly increasing if $a > 0$.

The function $f(x) = ax + b$ is strictly increasing for all real $x$ if

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