The frequency of oscillation of a mass $m$ suspended by a spring is $'v'$. If mass is cut to one fourth then what will be the frequency of oscillation ?
The frequency of oscillation of a mass $m$ suspended by a spring is $'v'$. If mass is cut to one fourth then what will be the frequency of oscillation ?
The frequency of oscillation of a mass suspended by a spring
$v=\frac{1}{2 \pi} \sqrt{\frac{k}{m}}$
$\therefore v \propto \frac{1}{\sqrt{m}}$
$\therefore \quad\frac{v_{2}}{v_{1}}=\sqrt{\frac{m_{1}}{m_{2}}}=\sqrt{\frac{m_{1}}{m_{1}}}=\sqrt{4}=2$
$\therefore \quad v_{2}=2 v\left[\because v_{1}=v\right]$
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