The formation of gas at the surface of tungsten due to adsorption is the reaction of order
The formation of gas at the surface of tungsten due to adsorption is the reaction of order
- [AIEEE 2002]
- A
$0$
- B
$1$
- C
$2$
- D
insufficient data
Similar Questions
The mechanism of the reaction $A + 2B \to D$ is
$2B\xrightarrow{k}{B_2}\,\left[ {Slow} \right]$
${B_2} + A \to D\,\left[ {Fast} \right]$
The rate law expression, order with respect to $A$, order with respect to $'B'$ and overall order of reaction are respectively
The mechanism of the reaction $A + 2B \to D$ is
$2B\xrightarrow{k}{B_2}\,\left[ {Slow} \right]$
${B_2} + A \to D\,\left[ {Fast} \right]$
The rate law expression, order with respect to $A$, order with respect to $'B'$ and overall order of reaction are respectively
Assertion :The order of a reaction can have fractional value.
Reason : The order of a reaction cannot be written from balanced equation of a reaction.
Assertion :The order of a reaction can have fractional value.
Reason : The order of a reaction cannot be written from balanced equation of a reaction.
- [AIIMS 2008]
If the surface area of the reactants increases, then order of the reaction
If the surface area of the reactants increases, then order of the reaction
Consider the kinetic data given in the following table for the reaction $A + B + C \rightarrow$ Product.
Experiment No.
$\begin{array}{c}{[ A ]} \\ \left( mol dm ^{-3}\right)\end{array}$
$\begin{array}{c}{[ B ]} \\ \left( mol dm ^{-3}\right)\end{array}$
$\begin{array}{c}{[ C]} \\ \left( mol dm ^{-3}\right)\end{array}$
Rate of reaction $\left( mol dm ^{-3} s ^{-1}\right)$
$1$
$0.2$
$0.1$
$0.1$
$6.0 \times 10^{-5}$
$2$
$0.2$
$0.2$
$0.1$
$6.0 \times 10^{-5}$
$3$
$0.2$
$0.1$
$0.2$
$1.2 \times 10^{-4}$
$4$
$0.3$
$0.1$
$0.1$
$9.0 \times 10^{-5}$
The rate of the reaction for $[ A ]=0.15 mol dm ^{-3},[ B ]=0.25 mol dm ^{-3}$ and $[ C ]=0.15 mol dm ^{-3}$ is found to be $Y \times 10^{-5} mol dm d ^{-3} s ^{-1}$. The value of $Y$ i. . . . . . .
Consider the kinetic data given in the following table for the reaction $A + B + C \rightarrow$ Product.
| Experiment No. | $\begin{array}{c}{[ A ]} \\ \left( mol dm ^{-3}\right)\end{array}$ | $\begin{array}{c}{[ B ]} \\ \left( mol dm ^{-3}\right)\end{array}$ | $\begin{array}{c}{[ C]} \\ \left( mol dm ^{-3}\right)\end{array}$ | Rate of reaction $\left( mol dm ^{-3} s ^{-1}\right)$ |
| $1$ | $0.2$ | $0.1$ | $0.1$ | $6.0 \times 10^{-5}$ |
| $2$ | $0.2$ | $0.2$ | $0.1$ | $6.0 \times 10^{-5}$ |
| $3$ | $0.2$ | $0.1$ | $0.2$ | $1.2 \times 10^{-4}$ |
| $4$ | $0.3$ | $0.1$ | $0.1$ | $9.0 \times 10^{-5}$ |
The rate of the reaction for $[ A ]=0.15 mol dm ^{-3},[ B ]=0.25 mol dm ^{-3}$ and $[ C ]=0.15 mol dm ^{-3}$ is found to be $Y \times 10^{-5} mol dm d ^{-3} s ^{-1}$. The value of $Y$ i. . . . . . .
- [IIT 2019]
For the reaction system $2NO(g) + {O_2}(g) \to 2N{O_2}(g)$ volume is suddenly produced to half its value by increasing the pressure on it. If the reaction is of first order with respect to $O_2$ and second order with respect to $NO,$ the rate of reaction will
For the reaction system $2NO(g) + {O_2}(g) \to 2N{O_2}(g)$ volume is suddenly produced to half its value by increasing the pressure on it. If the reaction is of first order with respect to $O_2$ and second order with respect to $NO,$ the rate of reaction will
- [AIEEE 2003]