The force F acting on a particle of mass m is | vedclass

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Question

$\begin{array}{l}
Chenge\,in\,momentum\, = Area\,under\,F - graph\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,

Vedclass · Accepted Answer

$12$

Vedclass · Answer

$\begin{array}{l}
Chenge\,in\,momentum\, = Area\,under\,F - graph\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,in\,that\,{m{interval}}\
\,\,\,\,\,\,\, = Area\,of\,\Delta ABC - Area\,of\,{m{rectangle}}\,CDEF\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, + Area\,of\,{m{rectangle}}\,{m{FGHI}}\
\,\,\,\,\,\,\, = \,\frac{1}{2} 	imes 2 	imes 6 - 3 	imes 2 + 4 	imes 3 = 12\,N\,s
\end{array}$

The force $F$ acting on a particle of mass $m$ is indicated by the force-time graph shown below. The change in momentum of the particle over the time interval from zero to $8\, s$ is .......... $N-s$

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