A body of mass 5 ,kg is moving with a velocit | vedclass

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(A) Given:Mass $m = 5 \,kg$Initial velocity $\vec{v}_i = (2 \hat{i} + 6 \hat{j}) \,m/s$Final velocity $\vec{v}_f = (10 \hat{i} + 6 \hat{j}) \,m/s$The

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$40 \hat{i}$

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(A) Given:Mass $m = 5 \,kg$Initial velocity $\vec{v}_i = (2 \hat{i} + 6 \hat{j}) \,m/s$Final velocity $\vec{v}_f = (10 \hat{i} + 6 \hat{j}) \,m/s$The change in momentum $\Delta \vec{p}$ is given by the formula:$\Delta \vec{p} = m(\vec{v}_f - \vec{v}_i)$Substitute the given values:$\Delta \vec{p} = 5 	imes [(10 \hat{i} + 6 \hat{j}) - (2 \hat{i} + 6 \hat{j})]$$\Delta \vec{p} = 5 	imes [(10 - 2) \hat{i} + (6 - 6) \hat{j}]$$\Delta \vec{p} = 5 	imes [8 \hat{i} + 0 \hat{j}]$$\Delta \vec{p} = 40 \hat{i} \,kg \cdot m/s$Therefore,the change in momentum is $40 \hat{i} \,kg \cdot m/s$.

$A$ body of mass $5 \,kg$ is moving with a velocity of $\vec{v}=(2 \hat{i}+6 \hat{j}) \,m/s$ at $t=0 \,s$. After time $t=2 \,s$,the velocity of the body is $(10 \hat{i}+6 \hat{j}) \,m/s$. The change in momentum of the body is ......... $kg \cdot m/s$.

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