The following table provides the resistivity of three samples:
Sample$A$$B$$C$
Resistivity$1.6 \times 10^{-8} \Omega \cdot m$$5.2 \times 10^{-8} \Omega \cdot m$$100 \times 10^{-6} \Omega \cdot m$

Which of them is suitable for heating elements of electrical appliances and why?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(C) Sample $C$ is suitable for heating elements of electrical appliances.
Reason: Heating elements require materials with high resistivity so that they can produce a significant amount of heat when an electric current passes through them, according to Joule's Law of heating $(H = I^2Rt)$. Among the given samples, Sample $C$ has the highest resistivity $(100 \times 10^{-6} \Omega \cdot m)$, making it the most efficient choice for generating heat.

Explore More

Similar Questions

The rating of an electric heater is $1100 \ W, 220 \ V$. Calculate its resistance when it operates at $220 \ V$. Also,calculate the energy consumed in $kWh$ in the month of November,if the heater is used daily for four hours at the rated voltage.

Which of the following represents voltage?

State reasons for the following:
$(a)$ Tungsten is used for making bulb filaments.
$(b)$ Copper and aluminium are generally used for electricity transmission.
$(c)$ Alloys are commonly used in electrical heating devices such as electric iron and toaster.

An electric heater rated $1200 \ W$ operates $2 \ h$ per day. Find the cost of the energy required to operate it for $30$ days at ₹ $5.00$ per unit.

The resistivity of a material does not change if:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo