The following diagram indicates the energy levels of a certain atom when the system moves from $4E$ level to $E$. A photon of wavelength $\lambda _1$ is emitted. The wavelength of photon produced during it's transition from $\frac{7}{3}E$ level to $E$ is $\lambda_2$. The ratio $\frac{{{\lambda _1}}}{{{\lambda _2}}}$ will be
$\frac{9}{4}$
$\frac{4}{9}$
$\frac{3}{2}$
$\frac{7}{3}$
If in Rutherford’s experiment, the number of particles scattered at ${90^o}$ angle are $28$ per min, then number of scattered particles at an angle ${60^o}$ and ${120^o}$ will be
An alpha particle colliding with one of the electrons in a gold atom loses
In third orbit of hydrogen atom, de Broglie wavelength of electron is $\lambda $ then radius of third orbit is
The ratio of speed of an electron in ground state in Bohrs first orbit of hydrogen atom to velocity of light in air is
The transition from the state $n = 4$ to $n = 3$ in a hydrogen like atom results in ultraviolet radiation. Infrared radiation will be obtained in the transition