An alpha particle colliding with one of the e | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The mass of an alpha particle $(m_{\alpha} \approx 6.64 	imes 10^{-27} \ kg)$ is approximately $7300$ times larger than the mass of an electron $

Vedclass · Accepted Answer

Little of its energy

Vedclass · Answer

(C) The mass of an alpha particle $(m_{\alpha} \approx 6.64 	imes 10^{-27} \ kg)$ is approximately $7300$ times larger than the mass of an electron $(m_e \approx 9.11 	imes 10^{-31} \ kg)$.According to the laws of conservation of momentum and energy,when a very heavy particle collides with a very light particle,the energy transferred to the light particle is negligible.Therefore,the alpha particle loses only a very small fraction of its kinetic energy during the collision with an electron.Thus,the correct option is $C$.

An alpha particle colliding with one of the electrons in a gold atom loses

Similar Questions

An alpha nucleus of energy $\frac{1}{2}mv^2$ bombards a heavy nuclear target of charge $Ze$. Then the distance of closest approach for the alpha nucleus will be proportional to

What was the thickness of the gold foil used in the Geiger-Marsden scattering experiment?

Using Thomson's model of the atom,consider an atom consisting of two electrons,each of charge $-e$,embedded in a sphere of charge $+2e$ and radius $R$. In equilibrium,each electron is at a distance $d$ from the center of the atom. What is the equilibrium separation between the electrons?

What radioactive source did Geiger and Marsden use in the scattering experiment?

Calculate the number of atoms in $39.4$ $g$ of gold. The molar mass of gold is $197$ $g$ $mol^{-1}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module