The final product C in the following series o | vedclass

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(A) $1$. Reduction: Nitrobenzene $(C_6H_5NO_2)$ reacts with $Sn/HCl$ to form aniline $(C_6H_5NH_2)$,which is product $A$.$2$. Diazotization: Aniline r

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$1-$(phenylazo)naphthalen$-2-$ol

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(A) $1$. Reduction: Nitrobenzene $(C_6H_5NO_2)$ reacts with $Sn/HCl$ to form aniline $(C_6H_5NH_2)$,which is product $A$.$2$. Diazotization: Aniline reacts with $NaNO_2/HCl$ at $0-5 \ ^\circ C$ to form benzene diazonium chloride $(C_6H_5N_2^+Cl^-)$,which is product $B$.$3$. Coupling Reaction: Benzene diazonium chloride reacts with $\beta$-naphthol in the presence of $NaOH$ to form an azo dye. The coupling occurs at the ortho position relative to the $-OH$ group in $\beta$-naphthol,yielding $1-$(phenylazo)naphthalen$-2-$ol as the final product $C$.

The final product $C$ in the following series of reactions is:

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