Which one of the following compounds forms a | vedclass

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(C) Amines react with alkyl halides in excess to undergo exhaustive alkylation,resulting in the formation of a quaternary ammonium salt.Among the give

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$C_6H_5NH_2$

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(C) Amines react with alkyl halides in excess to undergo exhaustive alkylation,resulting in the formation of a quaternary ammonium salt.Among the given options,$C_6H_5NH_2$ (aniline) is an amine,which reacts with excess methyl iodide $(CH_3I)$ to form a quaternary ammonium salt as shown below:$C_6H_5NH_2 + 3CH_3I \rightarrow C_6H_5N^+(CH_3)_3I^- + 2HI$Ethers ($C_2H_5OCH_3$ and $(CH_3)_2CHOC_2H_5$) do not form quaternary salts under these conditions,and nitro compounds $(C_6H_5NO_2)$ are not nucleophilic enough to undergo this reaction.

Which one of the following compounds forms a quaternary salt on reacting with excess methyl iodide?

Similar Questions

In the reaction shown,the structure of the product $T$ is:

The correct order of basic strength is:

The reaction is shown below. What is $X$ (major)?
$C_6H_5-CONH-C_6H_5 \xrightarrow{Br_2/Fe} X \text{ (major)}$

Identify the reagent $R$ in the following reaction:
$C_6H_5NO_2 \xrightarrow{R} C_6H_5NHOH$

In the given set of reactions,the $IUPAC$ name of product '$Y$' is:
$2-\text{Bromopropane}$ $\xrightarrow[\text{alc. / heat}]{AgCN} X$ $\xrightarrow{LiAlH_4} Y$

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