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(C) The boiling point of a compound depends on the strength of intermolecular forces.$n-C_4H_{10}$ $(C)$ is an alkane and possesses only weak van der

Vedclass · Accepted Answer

$C < D < B < A$

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(C) The boiling point of a compound depends on the strength of intermolecular forces.$n-C_4H_{10}$ $(C)$ is an alkane and possesses only weak van der Waals forces,resulting in the lowest boiling point.$C_2H_5NHC_2H_5$ $(D)$ is a secondary amine; it exhibits hydrogen bonding,but the extent is less than that of a primary amine due to steric hindrance.$n-C_4H_9NH_2$ $(B)$ is a primary amine,which has stronger hydrogen bonding compared to the secondary amine $(D)$.$n-C_4H_9OH$ $(A)$ is an alcohol,which forms the strongest hydrogen bonds due to the high electronegativity of oxygen compared to nitrogen,resulting in the highest boiling point.Therefore,the increasing order of boiling points is $C < D < B < A$.

Arrange the following compounds according to increasing order of boiling points: $n-C_4H_9OH$ $(A)$,$n-C_4H_9NH_2$ $(B)$,$n-C_4H_{10}$ $(C)$,and $C_2H_5NHC_2H_5$ $(D)$.

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Identify $A$ and $B$ in the following reaction sequence:
$C_6H_5NH_2 + CH_3COCl$ $\rightarrow A$ $\xrightarrow{Br_2/H_2O} B$

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