The figure shows a mixture of blue,green,and | vedclass

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(A) The rays are incident normally on the first surface of the prism,so they pass undeviated and strike the hypotenuse at an angle of incidence $i = 4

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red color from blue and green

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(A) The rays are incident normally on the first surface of the prism,so they pass undeviated and strike the hypotenuse at an angle of incidence $i = 45^{\circ}$.For total internal reflection to occur at the second surface,the angle of incidence must be greater than the critical angle $(i > C)$.Given critical angles are $C_{red} = 46^{\circ}$,$C_{green} = 44^{\circ}$,and $C_{blue} = 43^{\circ}$.For red light: $i = 45^{\circ} For green light: $i = 45^{\circ} > C_{green} = 44^{\circ}$. Thus,green light will undergo total internal reflection.For blue light: $i = 45^{\circ} > C_{blue} = 43^{\circ}$. Thus,blue light will undergo total internal reflection.Since green and blue light undergo total internal reflection while red light emerges,the arrangement separates red color from blue and green colors.

The figure shows a mixture of blue,green,and red colored rays incident normally on a right-angled prism. The critical angles of the material of the prism for red,green,and blue are $46^{\circ}$,$44^{\circ}$,and $43^{\circ}$ respectively. The arrangement will separate:

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