$A$ ray of light passes from a medium $A$ having refractive index $1.6$ to the medium $B$ having refractive index $1.5$. The value of the critical angle of medium $A$ is . . . . . . .

  • A
    $\sin^{-1} \sqrt{\frac{16}{15}}$
  • B
    $\sin^{-1} \left(\frac{16}{15}\right)$
  • C
    $\sin^{-1} \left(\frac{1}{2}\right)$
  • D
    $\sin^{-1} \left(\frac{15}{16}\right)$

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Reason: $\mu = \frac{1}{\sin C}$,where $\mu$ is the refractive index of diamond with respect to the liquid.

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