A ray of light travelling in water is inciden | vedclass

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(C) When a light ray travels from a denser medium (water) to a rarer medium (air) and the angle of incidence $	heta$ is less than the critical angle,

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a reflected ray and a refracted ray and the angle between them would be less than $180^{\circ}-2 	heta$

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(C) When a light ray travels from a denser medium (water) to a rarer medium (air) and the angle of incidence $	heta$ is less than the critical angle,partial reflection and partial refraction occur.$1$. The reflected ray makes an angle $	heta$ with the normal in the water medium.$2$. The refracted ray makes an angle $r$ with the normal in the air medium. According to Snell's law,$n_w \sin 	heta = n_a \sin r$. Since $n_w > n_a$,it follows that $\sin r > \sin 	heta$,so $r > 	heta$.$3$. The angle between the reflected ray and the refracted ray is $\phi = 180^{\circ} - (	heta + r)$.$4$. Since $r > 	heta$,we have $	heta + r > 2	heta$.$5$. Therefore,$180^{\circ} - (	heta + r) $6$. Thus,the angle between the reflected and refracted rays is less than $180^{\circ} - 2	heta$.

$A$ ray of light travelling in water is incident on its surface open to air. The angle of incidence is $\theta$,which is less than the critical angle. Then there will be

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