The ether shown below when treated with HI pr | vedclass

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(B) The reaction of an ether with $HI$ involves the protonation of the ether oxygen followed by nucleophilic attack by the iodide ion $(I^-)$.In this

Vedclass · Accepted Answer

$A, D$

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(B) The reaction of an ether with $HI$ involves the protonation of the ether oxygen followed by nucleophilic attack by the iodide ion $(I^-)$.In this specific case,the ether is cyclohexyl benzyl ether. The cleavage occurs such that the more stable carbocation is formed,or the reaction proceeds via an $S_N1$ mechanism if a stable carbocation can be formed.The benzyl group $(C_6H_5CH_2-)$ can form a stable resonance-stabilized carbocation,so the $C-O$ bond between the benzyl carbon and the oxygen breaks.The products formed are cyclohexanol ($C_6H_{11}OH$,which corresponds to option $D$) and benzyl iodide ($C_6H_5CH_2I$,which corresponds to option $A$).Therefore,the products are $A$ and $D$.

The ether shown below when treated with $HI$ produces:

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