The product of the reaction CH_3-C(CH_3)_2-O- | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction of an ether with $HI$ follows the $S_N1$ mechanism when one of the alkyl groups is tertiary,as the tertiary carbocation is highly sta

Vedclass · Accepted Answer

$CH_3-OH + (CH_3)_3C-I$

Vedclass · Answer

(C) The reaction of an ether with $HI$ follows the $S_N1$ mechanism when one of the alkyl groups is tertiary,as the tertiary carbocation is highly stable. $1$. Protonation of the ether oxygen occurs: $(CH_3)_3C-O(H^+)-CH_3$. $2$. The bond between the tertiary carbon and oxygen breaks to form a stable tertiary carbocation $(CH_3)_3C^+$ and methanol $CH_3OH$. $3$. The iodide ion $I^-$ attacks the tertiary carbocation to form tert-butyl iodide $(CH_3)_3C-I$. Thus,the products are $CH_3OH$ and $(CH_3)_3C-I$.

The product of the reaction $CH_3-C(CH_3)_2-O-CH_3 \xrightarrow{cold \ HI}$ is:

Similar Questions

Ethers,when dissolved in cold concentrated sulfuric acid,form:

Which product is obtained by the reaction of acetic anhydride with diethyl ether in the presence of anhydrous $AlCl_3$?

When ethyl bromide is treated with dry $Ag_2O$,the main product is:

Identify $A$ and $B$ in the following reaction: $C_6H_5CH_2-O-C_6H_5 + HI \rightarrow A + B$

Predict the major product for the following reaction: $Ph-O-CH_2-CH_2-(C_6H_4)-NO_2 + HI \text{ (excess)} \rightarrow \text{Product}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module