CH_3OC_2H_5 and (CH_3)_3COCH_3 are treated wi | vedclass

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(A) The reaction of ethers with $HI$ involves the cleavage of the $C-O$ bond.For the first ether,$CH_3-O-C_2H_5$,the reaction follows the $S_N2$ mecha

Vedclass · Accepted Answer

$CH_3I + C_2H_5OH$; $(CH_3)_3CI + CH_3OH$

Vedclass · Answer

(A) The reaction of ethers with $HI$ involves the cleavage of the $C-O$ bond.For the first ether,$CH_3-O-C_2H_5$,the reaction follows the $S_N2$ mechanism,where the iodide ion attacks the less sterically hindered alkyl group,forming $CH_3I + C_2H_5OH$.For the second ether,$(CH_3)_3C-O-CH_3$,the reaction follows the $S_N1$ mechanism because the tert-butyl carbocation is highly stable,leading to the formation of $(CH_3)_3CI + CH_3OH$.

$CH_3OC_2H_5$ and $(CH_3)_3COCH_3$ are treated with hydroiodic acid. The fragments obtained after reactions are:

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