The escape velocity for a body of mass 1, kg | vedclass

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Question

(B) The formula for escape velocity $(v_e)$ is given by $v_e = \sqrt{\frac{2GM}{R}}$,where $G$ is the universal gravitational constant,$M$ is the mass

Vedclass · Accepted Answer

$11.2\, km/s$

Vedclass · Answer

(B) The formula for escape velocity $(v_e)$ is given by $v_e = \sqrt{\frac{2GM}{R}}$,where $G$ is the universal gravitational constant,$M$ is the mass of the Earth,and $R$ is the radius of the Earth.As seen from the formula,the escape velocity depends only on the mass and radius of the planet (or celestial body) from which the object is being launched.It is independent of the mass of the object being launched.Therefore,for a body of mass $100\, kg$,the escape velocity remains the same as that for a body of mass $1\, kg$,which is $11.2\, km/s$.

The escape velocity for a body of mass $1\, kg$ from the earth's surface is $11.2\, km/s$. The escape velocity for a body of mass $100\, kg$ would be:

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