The equation of the polar of (1, 1) with resp | vedclass

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(D) Given,the equation of the circle is $x^2+y^2+4x+6y-3=0$. Given,the point is $P(1, 1)$. The equation of the polar of a point $(x_1, y_1)$ with resp

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$3x + 4y + 2 = 0$

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(D) Given,the equation of the circle is $x^2+y^2+4x+6y-3=0$. Given,the point is $P(1, 1)$. The equation of the polar of a point $(x_1, y_1)$ with respect to the circle $x^2+y^2+2gx+2fy+c=0$ is given by $x \cdot x_1 + y \cdot y_1 + g(x+x_1) + f(y+y_1) + c = 0$. Here,$g=2$,$f=3$,$c=-3$,$x_1=1$,and $y_1=1$. Substituting these values into the formula: $x(1) + y(1) + 2(x+1) + 3(y+1) - 3 = 0$ $x + y + 2x + 2 + 3y + 3 - 3 = 0$ $3x + 4y + 2 = 0$.

The equation of the polar of $(1, 1)$ with respect to the circle $x^2+y^2+4x+6y-3=0$ is

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