The equation of the directrix of the parabola $3x^{2} = 16y$ is

  • A
    $3y + 4 = 0$
  • B
    $3x + 4 = 0$
  • C
    $3y - 4 = 0$
  • D
    $3x - 4 = 0$

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Similar Questions

Three normals are drawn from the point $(3, 0)$ to the parabola $y^2 = 4x$,meeting the parabola at points $P, Q,$ and $R$. Match the following:
Column-$I$ Column-$II$
$(A)$ Circumradius of $\Delta PQR$ $(P)$ $5/2$
$(B)$ Area of $\Delta PQR$ $(Q)$ $(5/2, 0)$
$(C)$ Centroid of $\Delta PQR$ $(R)$ $(2/3, 0)$
$(D)$ Circumcenter of $\Delta PQR$ $(S)$ $2$

$A$ tangent to the curve $x = a t^{2}, y = 2 a t$ is perpendicular to the $X$-axis. Then the point of contact is:

The equations $x = \frac{t}{4}$ and $y = \frac{t^2}{4}$ represent:

If two tangents drawn from a point $P$ to the parabola $y^{2}=16(x-3)$ are at right angles,then the locus of point $P$ is :

$PQ$ is a focal chord of the parabola $y^2 = 4x$ with focus $S$. If $P = (4, 4)$,then $SQ = $

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