The equation of the line passing through (c, | vedclass

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(C) The given line is $ax + by + c = 0$. Its slope is $m = -\frac{a}{b}$. Since the required line is parallel to the given line,its slope will also be

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$a(x - c) + b(y - d) = 0$

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(C) The given line is $ax + by + c = 0$. Its slope is $m = -\frac{a}{b}$. Since the required line is parallel to the given line,its slope will also be $m = -\frac{a}{b}$. The equation of a line passing through $(c, d)$ with slope $m$ is given by $y - d = m(x - c)$. Substituting $m = -\frac{a}{b}$,we get $y - d = -\frac{a}{b}(x - c)$. Multiplying both sides by $b$,we get $b(y - d) = -a(x - c)$. Rearranging the terms,we get $a(x - c) + b(y - d) = 0$.

The equation of the line passing through $(c, d)$ and parallel to $ax + by + c = 0$ is

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