The equation of a simple harmonic progressive | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given equation of the wave is $y=A \sin (100 \pi t-3 x)$.Comparing this with the standard wave equation $y=A \sin (\omega t-kx)$,we get the wa

Vedclass · Accepted Answer

$\frac{\pi}{9} \ m$

Vedclass · Answer

(A) The given equation of the wave is $y=A \sin (100 \pi t-3 x)$.Comparing this with the standard wave equation $y=A \sin (\omega t-kx)$,we get the wave number $k=3 \ m^{-1}$.The relationship between phase difference $(\Delta \phi)$ and path difference $(\Delta x)$ is given by $\Delta \phi = k \cdot \Delta x$.Given the phase difference $\Delta \phi = \frac{\pi}{3}$.Substituting the values,we have $\frac{\pi}{3} = 3 \cdot \Delta x$.Solving for the distance $\Delta x$,we get $\Delta x = \frac{\pi}{3 	imes 3} = \frac{\pi}{9} \ m$.

The equation of a simple harmonic progressive wave is given by $y=A \sin (100 \pi t-3 x)$. Find the distance between $2$ particles having a phase difference of $\frac{\pi}{3}$.

Similar Questions

$A$ wave is represented by the equation: $y = a \sin(0.01x - 2t)$,where $a$ and $x$ are in $cm$. The velocity of propagation of the wave is .... $cm/s$.

The displacement $y$ (in $cm$) in case of a simple harmonic wave is given by $y=\frac{10}{\pi} \sin \left(2000 \pi t-\frac{\pi x}{17}\right)$. The period and maximum velocity of the particles in the medium will respectively be

Two sound waves having a phase difference of $60^{\circ}$ have a path difference of

The frequency of the sinusoidal wave $y = 0.40\cos(2000t + 0.80x)$ is

Define the angular wave number and provide its mathematical equation.

Vedclass Test Series

Exam Paper Generator

Online Exam Module