The frequency of the sinusoidal wave y = 0.40 | vedclass

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Question

(D) The standard form of a sinusoidal wave equation is $y = a \cos(\omega t + kx + \phi)$.Comparing the given equation $y = 0.40 \cos(2000t + 0.80x)$

Vedclass · Accepted Answer

$\frac{1000}{\pi} 	ext{ Hz}$

Vedclass · Answer

(D) The standard form of a sinusoidal wave equation is $y = a \cos(\omega t + kx + \phi)$.Comparing the given equation $y = 0.40 \cos(2000t + 0.80x)$ with the standard form,we identify the angular frequency $\omega = 2000 	ext{ rad/s}$.The relationship between angular frequency $\omega$ and frequency $f$ is given by $\omega = 2\pi f$.Substituting the value of $\omega$,we get $2000 = 2\pi f$.Solving for $f$,we find $f = \frac{2000}{2\pi} = \frac{1000}{\pi} 	ext{ Hz}$.

The frequency of the sinusoidal wave $y = 0.40\cos(2000t + 0.80x)$ is

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