Easy
The electronic configuration of the valence shell of $Cu$ is $3d^{10}4s^{1}$ and not $3d^{9}4s^{2}$. How is this configuration explained?
- ADue to the stability of completely filled $d$-orbitals.
- BDue to the stability of half-filled $d$-orbitals.
- CDue to the exchange energy.
- DDue to the lower energy of $3d$ orbitals compared to $4s$.
Explore More
Similar Questions
Write about $p$-orbitals.
Difficult
View SolutionThe relation between $n_m$ (the number of permissible values of magnetic quantum number $m$) for a given value of azimuthal quantum number $l$ is:
MediumNEET 2023
View SolutionWhich of the following orbitals is non-directional?
Easy
View SolutionThe correct ground state electronic configuration of chromium atom is
MediumIIT 1989
View SolutionThe maximum number of orbitals present in $n=4$ energy level of an atom and the maximum number of electrons with spin value $+\frac{1}{2}$ in the same orbitals are,respectively.
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo