The maximum number of orbitals present in n=4 | vedclass

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(D) For a given energy level $n$,the total number of orbitals is given by $n^2$.For $n=4$,the total number of orbitals $= 4^2 = 16$.Each orbital can h

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$16, 16$

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(D) For a given energy level $n$,the total number of orbitals is given by $n^2$.For $n=4$,the total number of orbitals $= 4^2 = 16$.Each orbital can hold a maximum of $2$ electrons with opposite spins,i.e.,$+\frac{1}{2}$ and $-\frac{1}{2}$.Since there are $16$ orbitals,the total number of electrons is $16 	imes 2 = 32$.Out of these $32$ electrons,exactly half will have a spin value of $+\frac{1}{2}$.Therefore,the number of electrons with spin $+\frac{1}{2} = \frac{32}{2} = 16$.Thus,the values are $16$ and $16$.

The maximum number of orbitals present in $n=4$ energy level of an atom and the maximum number of electrons with spin value $+\frac{1}{2}$ in the same orbitals are,respectively.

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