The distance between the foci of an ellipse is 16 and eccentricity is $\frac{1}{2}$. Length of the major axis of the ellipse is

  • A

    $8$

  • B

    $64$

  • C

    $16$

  • D

    $32$

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Let the product of the focal distances of the point $\left(\sqrt{3}, \frac{1}{2}\right)$ on the ellipse $\frac{ x ^2}{ a ^2}+\frac{ y ^2}{b^2}=1,( a > b )$, be $\frac{7}{4}$. Then the absolute difference of the eccentricities of two such ellipses is

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The equations of the directrices of the ellipse $16{x^2} + 25{y^2} = 400$ are

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