The distance between an object and a divergen | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For a divergent (concave) lens,the focal length $f$ is taken as negative,so $f_{lens} = -f$ (where $f > 0$).Given the object distance $u = -mf$.Us

Vedclass · Accepted Answer

$\frac{1}{m+1}$

Vedclass · Answer

(D) For a divergent (concave) lens,the focal length $f$ is taken as negative,so $f_{lens} = -f$ (where $f > 0$).Given the object distance $u = -mf$.Using the lens formula: $\frac{1}{v} - \frac{1}{u} = \frac{1}{f_{lens}}$.Substituting the values: $\frac{1}{v} - \frac{1}{-mf} = \frac{1}{-f}$.$\frac{1}{v} + \frac{1}{mf} = -\frac{1}{f}$.$\frac{1}{v} = -\frac{1}{f} - \frac{1}{mf} = -\frac{1}{f} \left(1 + \frac{1}{m}\right) = -\frac{1}{f} \left(\frac{m+1}{m}\right)$.Therefore,$v = -f \left(\frac{m}{m+1}\right)$.The linear magnification $M$ is given by $M = \frac{v}{u}$.$M = \frac{-f \left(\frac{m}{m+1}\right)}{-mf} = \frac{1}{m+1}$.

The distance between an object and a divergent lens is $m$ times the focal length of the lens. The linear magnification produced by the lens is

Similar Questions

For a concave lens of focal length $f$,the relation between object distance $u$ and image distance $v$ from its pole can best be represented by ($u = v$ is the reference line):

$A$ magnifying lens has a focal length of $10 \, cm$. If the image is formed at a distance of $30 \, cm$ from the lens,what is the magnification?

Photographs of the ground are taken from an aircraft flying at an altitude of $2000\; m$ by a camera with a lens of focal length $50\; cm$. The size of the film in the camera is $18\; cm \times 18\; cm$. The area of the ground that can be photographed by the camera is

$A$ luminous object is separated from a screen by a distance $d$. $A$ convex lens is placed between the object and the screen such that it forms a distinct image on the screen. The maximum possible focal length of this convex lens is

If the aperture of a lens is halved,then the image will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module