The displacement of a particle performing $S.H.M.$ is given by $x=5 \sin (3 t+3)$,where $x$ is in $cm$ and $t$ is in $s$. The maximum acceleration of the particle will be (in $cm \ s^{-2}$)

$A$ particle is executing simple harmonic motion with an amplitude of $0.1 \, m$. At a certain instant when its displacement is $0.02 \, m$,its acceleration is $0.5 \, m/s^2$. The maximum velocity of the particle is (in $m/s$):

$A$ particle of mass $10 \text{ g}$ is executing simple harmonic motion with an amplitude of $0.5 \text{ m}$ and a periodic time of $(\pi / 5) \text{ s}$. The maximum value of the force acting on the particle is ... $N$.

$A$ coin is placed on a horizontal platform which undergoes vertical simple harmonic motion of angular frequency $\omega$. The amplitude of oscillation is gradually increased. The coin will leave contact with the platform for the first time

The acceleration-displacement graph of a particle executing $SHM$ is shown in the figure. The time period of the simple harmonic motion is:

$A$ particle of mass $1 \ kg$ is moving in $SHM$ with a path length of $0.01 \ m$ and frequency of $50 \ Hz$. The maximum force in newton,acting on the particle is (in $\pi^2$)