(C) The acceleration $a$ of a particle in simple harmonic motion is given by $a = \omega^2 y$,where $\omega$ is the angular frequency and $y$ is the d

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(C) The acceleration $a$ of a particle in simple harmonic motion is given by $a = \omega^2 y$,where $\omega$ is the angular frequency and $y$ is the displacement.Given $a = 0.5 \, m/s^2$ and $y = 0.02 \, m$.$\omega^2 = \frac{a}{y} = \frac{0.5}{0.02} = 25$.$\omega = \sqrt{25} = 5 \, rad/s$.The maximum velocity $v_{\max}$ is given by $v_{\max} = A\omega$,where $A$ is the amplitude.Given $A = 0.1 \, m$.$v_{\max} = 0.1 \times 5 = 0.5 \, m/s$.

Class 11 Physics Oscillations Acceleration and Force of Simple Harmonic Motion

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$A$ particle is executing simple harmonic motion with an amplitude of $0.1 \, m$. At a certain instant when its displacement is $0.02 \, m$,its acceleration is $0.5 \, m/s^2$. The maximum velocity of the particle is (in $m/s$):

A
$0.01$
B
$0.05$
C
$0.5$
D
$0.25$

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Acceleration and Force of Simple Harmonic Motion

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For a particle executing simple harmonic motion given by $y(cm) = \sin \frac{\pi}{2} \left( \frac{t}{2} + \frac{1}{3} \right)$,what is the maximum acceleration in $cm/sec^2$?

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The acceleration of a particle performing $S.H.M.$ at a distance of $3\;cm$ from the mean position is $12\;cm/s^2$. Its time period is ..... $s$.

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Which one of the following statements is true for the speed $v$ and the acceleration $a$ of a particle executing simple harmonic motion?

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$A$ particle of mass $5 \,g$ is executing $S.H.M.$ with an amplitude $0.3 \,m$ and period $\frac{\pi}{5} \,s$. The maximum value of the force acting on the particle is (in $\,N$)

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$A$ particle is executing simple harmonic motion with an amplitude of $0.1 \, m$. At a certain instant when its displacement is $0.02 \, m$,its acceleration is $0.5 \, m/s^2$. The maximum velocity of the particle is (in $m/s$):

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$A$ point mass oscillates along the $X$-axis according to the law $x=x_0 \cos \left(\omega t-\frac{\pi}{4}\right)$. If the acceleration of the particle is written as $a=A \cos (\omega t-\delta)$,then

For a particle executing simple harmonic motion given by $y(cm) = \sin \frac{\pi}{2} \left( \frac{t}{2} + \frac{1}{3} \right)$,what is the maximum acceleration in $cm/sec^2$?

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Which one of the following statements is true for the speed $v$ and the acceleration $a$ of a particle executing simple harmonic motion?

$A$ particle of mass $5 \,g$ is executing $S.H.M.$ with an amplitude $0.3 \,m$ and period $\frac{\pi}{5} \,s$. The maximum value of the force acting on the particle is (in $\,N$)

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