Two particles $A$ and $B$ start from rest and move for equal time on a straight line. Particle $A$ has an acceleration of $2\,m / s ^2$ for the first half of the total time and $4\,m / s ^2$ for the second half. The particle $B$ has acceleration $4\,m / s ^2$ for the first half and $2\,m / s ^2$ for the second half. Which particle has covered larger distance?
- A$A$
- B$B$
- CBoth have covered the same distance
- DData insufficient
Similar Questions
A particle moves along a straight line such that its displacement at any time $t$ is given by $s = (t^3 -6t^2 + 3t + 4)\, m$. ...... $m/s$ is the velocity of the particle when its acceleration is zero ................. $\mathrm{m/s}$
Acceleration-time graph for a particle is given in figure. If it starts motion at $t=0$, distance travelled in $3 \,s$ will be ........... $m$
Acceleration-time graph for a particle is given in figure. If it starts motion at $t=0$, distance travelled in $3 \,s$ will be ........... $m$
Read each statement below carefully and state with reasons and examples, if it is true or false
A particle in one-dimensional motion
$(a)$ with zero speed at an instant may have non-zero acceleration at that instant
$(b)$ with zero speed may have non-zero velocity.
$(c)$ with constant speed must have zero acceleration.
$(d)$ with positive value of acceleration must be speeding up.
Read each statement below carefully and state with reasons and examples, if it is true or false
A particle in one-dimensional motion
$(a)$ with zero speed at an instant may have non-zero acceleration at that instant
$(b)$ with zero speed may have non-zero velocity.
$(c)$ with constant speed must have zero acceleration.
$(d)$ with positive value of acceleration must be speeding up.
The velocity-time graph for a particle moving along $x$-axis is shown in the figure. The corresponding displacement-time graph is correctly shown by
A particle initially at rest starts moving from reference point. $\mathrm{x}=0$ along $\mathrm{x}$-axis, with velocity $v$ that varies as $v=4 \sqrt{\mathrm{x} m} / \mathrm{s}$. The acceleration of the particle is __________$ \mathrm{ms}^{-2}$.
A particle initially at rest starts moving from reference point. $\mathrm{x}=0$ along $\mathrm{x}$-axis, with velocity $v$ that varies as $v=4 \sqrt{\mathrm{x} m} / \mathrm{s}$. The acceleration of the particle is __________$ \mathrm{ms}^{-2}$.
- [JEE MAIN 2024]