The displacement (x) of a particle depends on | vedclass

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Question

(d)

$x=0$ at $t=0$ and $t=\alpha / \beta$. So, the particle returns to starting point at $t=\alpha / \beta$

$v=\frac{d x}{d t}=2 \alpha t-3 \bet

Vedclass · Accepted Answer

$(a)$ and $(c)$ Only

Vedclass · Answer

(d)

$x=0$ at $t=0$ and $t=\alpha / \beta$. So, the particle returns to starting point at $t=\alpha / \beta$

$v=\frac{d x}{d t}=2 \alpha t-3 \beta t^2$

At $t=0, v=0$ i.e. initial velocity of particle is zero.

$v=0$ at $t=0$ and $t=\frac{2 \alpha}{2 \beta}$

Thus, the particle comes to rest after time

$t=2 \alpha / 3 \beta$

$a=\frac{d v}{d t}=2 \alpha-6 \beta t$

At $t=0, a=2 a 
eq 0$

The displacement $(x)$ of a particle depends on time $t$ as $x=\alpha t^2-\beta t^3$. Choose the incorrect statements from the following.

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