The displacement x of a particle in a straigh | vedclass

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Question

(b)
$\frac{d x}{d t}=v=-1-2\,t$
Comparing with $v=u+a t$, we have, $u=-1\,m / s$ and $a=-2\,m / s ^2$
At $t=0, x=1\,m$. Then, $u$ and $a$ both are

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Vedclass · Answer

(b)
$\frac{d x}{d t}=v=-1-2\,t$
Comparing with $v=u+a t$, we have, $u=-1\,m / s$ and $a=-2\,m / s ^2$
At $t=0, x=1\,m$. Then, $u$ and $a$ both are negative. Hence, $x$-coordinate of particle will go on decreasing.

The displacement $x$ of a particle in a straight line motion is given by $x=1-t-t^2$. The correct representation of the motion is $..............$.

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