The digit in the unit place of the number 843 | vedclass

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(D) To find the unit digit of $843^{843}$,we look at the unit digit of $3^{843}$. The powers of $3$ follow a cycle of $4$: $3^1=3, 3^2=9, 3^3=27, 3^4=

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$5$

Vedclass · Answer

(D) To find the unit digit of $843^{843}$,we look at the unit digit of $3^{843}$. The powers of $3$ follow a cycle of $4$: $3^1=3, 3^2=9, 3^3=27, 3^4=81$. $843 \div 4$ leaves a remainder of $3$,so the unit digit of $3^{843}$ is the same as $3^3$,which is $7$. To find the unit digit of $492^{295}$,we look at the unit digit of $2^{295}$. The powers of $2$ follow a cycle of $4$: $2^1=2, 2^2=4, 2^3=8, 2^4=16$. $295 \div 4$ leaves a remainder of $3$,so the unit digit of $2^{295}$ is the same as $2^3$,which is $8$. The unit digit of the sum is the unit digit of $(7 + 8) = 15$,which is $5$.

The digit in the unit place of the number $843^{843} + 492^{295}$ is:

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