If $2^{n}$ divides $16!$ and $2^{n+1}$ does not divide $16!$,then $n=$

The sum of all positive divisors of $242$ except $1$ and itself is:

The number of positive odd divisors of $216$ is

Consider the following statements:
$I$: The number of non-trivial even divisors of the number $N = 2^{\alpha_1} 3^{\alpha_2} 4^{\alpha_3} 5^{\alpha_4} 6^{\alpha_5}$ is $(\alpha_1+2\alpha_3+\alpha_5)(\alpha_2+\alpha_5+1)(\alpha_4+1)-1$.
$II$: The number of non-trivial odd divisors of the number $N = 2^{\alpha_1} 3^{\alpha_2} 4^{\alpha_3} 5^{\alpha_4} 6^{\alpha_5}$ is $\alpha_2+\alpha_4+\alpha_5+\alpha_2\alpha_4+\alpha_4\alpha_5$. Then:

The sum of the divisors of $9000$ is . . . . . . .

The number of $3$-digit numbers that are divisible by $2$ and $3$,but not divisible by $4$ and $9$,is