The differential equation of the family of curves represented by the equation ${x^2} + {y^2} = {a^2}$ is
- A$x + y\frac{dy}{dx} = 0$
- B$y\frac{dy}{dx} = x$
- C$y\frac{d^2y}{dx^2} + \left( \frac{dy}{dx} \right)^2 = 0$
- DNone of these
Explore More
Similar Questions
If $k$ and $l$ respectively are the order and degree of the differential equation whose general solution represents the family of circles of constant radius,then $k^2+l^2=$
The difference between the degree and the order of the differential equation that represents the family of curves given by $y^{2}=a\left(x+\frac{\sqrt{a}}{2}\right)$,where $a>0$,is:
If the differential equation representing the family of all circles touching the $x-$axis at the origin is $(x^2 - y^2)\frac{dy}{dx} = g(x)y$,then $g(x)$ equals
DifficultJEE MAIN 2014
View SolutionThe differential equation of the family of parabolas with focus at the origin and the $X$-axis as axis,is
The differential equation of all circles which pass through the origin and whose centres lie on the $y$-axis is:
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo