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(B) Given that $f(x) = \log x.$We need to find the derivative of $f(\sin x)$ with respect to $x.$Let $y = f(\sin x) = \log(\sin x).$Using the chain ru

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$\cot x$

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(B) Given that $f(x) = \log x.$We need to find the derivative of $f(\sin x)$ with respect to $x.$Let $y = f(\sin x) = \log(\sin x).$Using the chain rule,we differentiate with respect to $x$:$\frac{dy}{dx} = \frac{d}{dx}[\log(\sin x)]$$\frac{dy}{dx} = \frac{1}{\sin x} \cdot \frac{d}{dx}(\sin x)$$\frac{dy}{dx} = \frac{1}{\sin x} \cdot \cos x$$\frac{dy}{dx} = \cot x.$Therefore,the correct option is $B$.

The differential coefficient of $f(\sin x)$ with respect to $x,$ where $f(x) = \log x,$ is

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