The difference between two numbers is 9 and t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the two numbers be $x$ and $y$,where $x > y$.According to the problem:$x - y = 9$  ---(Equation $1$)$x^2 - y^2 = 207$  ---(Equation $2$)We kno

Vedclass · Accepted Answer

$16$ and $7$

Vedclass · Answer

(B) Let the two numbers be $x$ and $y$,where $x > y$.According to the problem:$x - y = 9$  ---(Equation $1$)$x^2 - y^2 = 207$  ---(Equation $2$)We know that $x^2 - y^2 = (x + y)(x - y)$.Substituting the values from Equation $1$ into Equation $2$:$(x + y)(9) = 207$$x + y = 207 / 9 = 23$  ---(Equation $3$)Now,add Equation $1$ and Equation $3$:$(x - y) + (x + y) = 9 + 23$$2x = 32$$x = 16$Substitute $x = 16$ into Equation $1$:$16 - y = 9$$y = 16 - 9 = 7$Therefore,the numbers are $16$ and $7$.

The difference between two numbers is $9$ and the difference between their squares is $207$. The numbers are

Similar Questions

If $x = 3 - 2\sqrt{2}$,then $\sqrt{x} + \frac{1}{\sqrt{x}}$ is equal to

What will come in the place of the question mark $(?)$ in the following equation?
$2 \frac{1}{8} - 1 \frac{1}{16} = ? + 1 \frac{1}{32} - 1 \frac{9}{64}$

If the numbers $\frac{3}{5}, \frac{2}{3}, \frac{3}{4}$ are given,then we can say that

$34.95 + 240.016 + 23.98 = ?$

If the square of the sum of three positive consecutive natural numbers exceeds the sum of their squares by $292$,then what is the largest of the three numbers?

Vedclass Test Series

Exam Paper Generator

Online Exam Module