The decomposition of $NH _{3}$ on $Pt$ surface is a zero order reaction. If the value of rate constant is $2 \times 10^{-4}\,mole $ $liter^{-1}\, sec ^{-1}$ The rate of appearance of $N _{2}$ and $H _{2}$ are respectively.

  • [AIIMS 2019]
  • A

    $N_2=$ $1 \times 10^{-4} \,mol ^{-1} \,sec ^{-1}$;

    $H_2=$ $3 \times 10^{-4} \,mol ^{-1} \,sec ^{-1}$

  • B

    $N_2=$ $3 \times 10^{-4} \,mol ^{-1} \,sec ^{-1}$;

    $H_2=$ $1 \times 10^{-4} \,mol ^{-1} \,sec ^{-1}$

  • C

    $N_2=$ $2 \times 10^{-4} \,mol ^{-1} \,sec ^{-1}$;

    $H_2=$ $6 \times 10^{-4} \,mol ^{-1} \,sec ^{-1}$

  • D

    $N_2=$ $3 \times 10^{-4}\,mol ^{-1} \,sec ^{-1}$;

    $H_2=$ $3 \times 10^{-4}\,mol ^{-1} \,sec ^{-1}$

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  • [JEE MAIN 2023]

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