The decomposition of $NH_3$ on $Pt$ surface is a zero order reaction. If the value of rate constant is $2 \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$,the rates of appearance of $N_2$ and $H_2$ are respectively:

  • A
    $N_2 = 1 \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$; $H_2 = 3 \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$
  • B
    $N_2 = 3 \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$; $H_2 = 1 \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$
  • C
    $N_2 = 2 \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$; $H_2 = 6 \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$
  • D
    $N_2 = 3 \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$; $H_2 = 3 \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$

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