The data is obtained in tabular form as follo | vedclass

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(A) Let $A = 64$ and $h = 1$. We define $y_i = \frac{x_i - 64}{1}$.$x_i$$f_i$$y_i$$f_i y_i$$f_i y_i^2$$60$$2$$-4$$-8$$32$$61$$1$$-3$$-3$$9$$62$$12$$-2

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(A) Let $A = 64$ and $h = 1$. We define $y_i = \frac{x_i - 64}{1}$.$x_i$$f_i$$y_i$$f_i y_i$$f_i y_i^2$$60$$2$$-4$$-8$$32$$61$$1$$-3$$-3$$9$$62$$12$$-2$$-24$$48$$63$$29$$-1$$-29$$29$$64$$25$$0$$0$$0$$65$$12$$1$$12$$12$$66$$10$$2$$20$$40$$67$$4$$3$$12$$36$$68$$5$$4$$20$$80$Total$N=100$-$\sum f_i y_i = 0$$\sum f_i y_i^2 = 286$Mean $\bar{x} = A + \frac{\sum f_i y_i}{N} 	imes h = 64 + \frac{0}{100} 	imes 1 = 64$.Variance $\sigma^2 = \frac{h^2}{N^2} [N \sum f_i y_i^2 - (\sum f_i y_i)^2] = \frac{1^2}{100^2} [100 	imes 286 - 0^2] = \frac{28600}{10000} = 2.86$.Standard deviation $\sigma = \sqrt{2.86} \approx 1.69$.

The data is obtained in tabular form as follows:
$x_i$ $60$ $61$ $62$ $63$ $64$ $65$ $66$ $67$ $68$
$f_i$ $2$ $1$ $12$ $29$ $25$ $12$ $10$ $4$ $5$

Find the standard deviation of the given data. (in $.69$)

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$x_i$	$60$	$61$	$62$	$63$	$64$	$65$	$66$	$67$	$68$
$f_i$	$2$	$1$	$12$	$29$	$25$	$12$	$10$	$4$	$5$

The data is obtained in tabular form as follows:$x_i$$60$$61$$62$$63$$64$$65$$66$$67$$68$$f_i$$2$$1$$12$$29$$25$$12$$10$$4$$5$Find the standard deviation of the given data. (in $.69$)