The curve between charge density rho and dist | vedclass

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(A) In a $p-n$ junction,the depletion region is formed due to the diffusion of charge carriers. On the $p$-side of the junction,there are negatively c

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(A) In a $p-n$ junction,the depletion region is formed due to the diffusion of charge carriers. On the $p$-side of the junction,there are negatively charged acceptor ions,which create a negative charge density. On the $n$-side of the junction,there are positively charged donor ions,which create a positive charge density. The charge density $\rho$ is negative on the $p$-side and positive on the $n$-side. At the junction interface $(r = 0)$,the charge density transitions from negative to positive. Therefore,the graph that shows a negative charge density on the $p$-side and a positive charge density on the $n$-side,passing through the origin,is the correct representation. This corresponds to the graph where the curve is below the $r$-axis for the $p$-region and above the $r$-axis for the $n$-region.

The curve between charge density $\rho$ and distance $r$ near a $p$ - $n$ junction is best represented by

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