The correct statement with regard to H_{2}^{+ | vedclass

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(D) $H_{2}^{+}$: Electronic configuration is $\sigma 1s^{1}$,$\sigma^{*} 1s^{0}$.Bond order $= \frac{1-0}{2} = 0.5$.$H_{2}^{-}$: Electronic configurat

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$H_{2}^{+}$ is more stable than $H_{2}^{-}$

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(D) $H_{2}^{+}$: Electronic configuration is $\sigma 1s^{1}$,$\sigma^{*} 1s^{0}$.Bond order $= \frac{1-0}{2} = 0.5$.$H_{2}^{-}$: Electronic configuration is $\sigma 1s^{2}$,$\sigma^{*} 1s^{1}$.Bond order $= \frac{2-1}{2} = 0.5$.Although the bond orders of $H_{2}^{+}$ and $H_{2}^{-}$ are the same,$H_{2}^{+}$ is more stable than $H_{2}^{-}$.This is because $H_{2}^{-}$ contains one electron in the antibonding molecular orbital $(\sigma^{*} 1s)$,which decreases its stability compared to $H_{2}^{+}$.

The correct statement with regard to $H_{2}^{+}$ and $H_{2}^{-}$ is

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