Which of the following species has the highes | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The bond order is calculated using the formula: $	ext{Bond Order} = \frac{N_b - N_a}{2}$,where $N_b$ is the number of bonding electrons and $N_a$

Vedclass · Accepted Answer

$O_2^+$

Vedclass · Answer

(C) The bond order is calculated using the formula: $	ext{Bond Order} = \frac{N_b - N_a}{2}$,where $N_b$ is the number of bonding electrons and $N_a$ is the number of antibonding electrons.$1. O_2$ ($16$ electrons): Configuration is $KK(\sigma 2s)^2(\sigma^* 2s)^2(\sigma 2p_z)^2(\pi 2p_x)^2(\pi 2p_y)^2(\pi^* 2p_x)^1(\pi^* 2p_y)^1$. Bond order $= \frac{10 - 6}{2} = 2$.$2. O_2^-$ ($17$ electrons): Configuration adds one electron to $\pi^* 2p_y$. Bond order $= \frac{10 - 7}{2} = 1.5$.$3. O_2^+$ ($15$ electrons): Configuration removes one electron from $\pi^* 2p_y$. Bond order $= \frac{10 - 5}{2} = 2.5$.$4. O_2^{2-}$ ($18$ electrons): Configuration adds two electrons to $\pi^* 2p_x$ and $\pi^* 2p_y$. Bond order $= \frac{10 - 8}{2} = 1$.Comparing the values,$O_2^+$ has the highest bond order of $2.5$.

Which of the following species has the highest bond order?

Similar Questions

Which of the following is paramagnetic?

In which of the following sets is the sum of bond orders of the three species maximum?

Using $MO$ theory,predict which of the following species has the shortest bond length?

The bond order in $N_2^+$ ion is

Which of the following species is not paramagnetic?

Vedclass Test Series

Exam Paper Generator

Online Exam Module