The correct pair of species with (A) the high | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To determine the bond order and magnetic character,we use Molecular Orbital Theory $(MOT)$. The total number of electrons for each species is:$O_2

Vedclass · Accepted Answer

$O_2^{+}, O_2^{2-}$

Vedclass · Answer

(B) To determine the bond order and magnetic character,we use Molecular Orbital Theory $(MOT)$. The total number of electrons for each species is:$O_2$ $(16 \ e^-)$: Bond order = $\frac{10-6}{2} = 2$,Paramagnetic.$O_2^{+}$ $(15 \ e^-)$: Bond order = $\frac{10-5}{2} = 2.5$,Paramagnetic.$O_2^{-}$ $(17 \ e^-)$: Bond order = $\frac{10-7}{2} = 1.5$,Paramagnetic.$O_2^{2-}$ $(18 \ e^-)$: Bond order = $\frac{10-8}{2} = 1$,Diamagnetic.$(A)$ The species with the highest bond order is $O_2^{+}$ (Bond order = $2.5$).$(B)$ The species with diamagnetic character is $O_2^{2-}$ (all electrons are paired).Therefore,the pair is $(O_2^{+}, O_2^{2-})$.

The correct pair of species with $(A)$ the highest bond order and $(B)$ diamagnetic character is

Similar Questions

Which of the following has a three-electron bond in its structure?

Explain the energy level diagram for molecular orbitals formed by $1s$ orbitals.

Which of the following species is not paramagnetic?

The bond order in $O_2^{2-}$ is

$AX$ is a covalent diatomic molecule where $A$ and $X$ are second row elements of the periodic table. Based on Molecular Orbital Theory,the bond order of $AX$ is $2.5$. The total number of electrons in $AX$ is ........... (Round off to the nearest integer).

Vedclass Test Series

Exam Paper Generator

Online Exam Module