The correct order of increasing bond angles i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) As the number of lone pairs of electrons increases,the bond angle decreases.$NO_2^+$ is isoelectronic with $CO_2$. It is a linear ion with $sp$-hy

Vedclass · Accepted Answer

$NO_2^- < NO_2 < NO_2^+$

Vedclass · Answer

(D) As the number of lone pairs of electrons increases,the bond angle decreases.$NO_2^+$ is isoelectronic with $CO_2$. It is a linear ion with $sp$-hybridization at the central $N$ atom,resulting in a bond angle of $180^{\circ}$.In $NO_2^-$,the $N$ atom undergoes $sp^2$-hybridization. Due to the presence of one lone pair,the bond angle is reduced from the ideal $120^{\circ}$ to approximately $115^{\circ}$.In $NO_2$,the $N$ atom has one unpaired electron in an $sp^2$-hybrid orbital. The bond angle is approximately $134^{\circ}$ (often cited as $132^{\circ}-134^{\circ}$),which is greater than $120^{\circ}$ due to the repulsion of the unpaired electron.Therefore,the increasing order of bond angles is $NO_2^- < NO_2 < NO_2^+$ $(115^{\circ} < 134^{\circ} < 180^{\circ})$.

The correct order of increasing bond angles in the following triatomic species is

Similar Questions

Which of the following triatomic molecules are linear? How is this determined?
$H_2O, F_2O, BeH_2, BeCl_2, H_2S, CO_2$

The number of species from the following which have a square pyramidal structure is $PF_{5}$,$BrF_{4}^{-}$,$IF_{5}$,$BrF_{5}$,$XeOF_{4}$,$ICl_{4}^{-}$.

Which of the following is $NOT$ tetrahedral in shape?

Amongst the following,the linear species is:

Which of the following is an incorrect statement about $PCl_5$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module