Which of the following is NOT tetrahedral in | vedclass

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(C) To determine the shape,we calculate the hybridization and number of lone pairs for each species:$1$. $NH_4^+$: Central atom $N$ has $5$ valence el

Vedclass · Accepted Answer

$SF_4$

Vedclass · Answer

(C) To determine the shape,we calculate the hybridization and number of lone pairs for each species:$1$. $NH_4^+$: Central atom $N$ has $5$ valence electrons. $H = (5+4-1)/2 = 4$. Hybridization is $sp^3$ with $0$ lone pairs,so it is tetrahedral.$2$. $SiCl_4$: Central atom $Si$ has $4$ valence electrons. $H = (4+4)/2 = 4$. Hybridization is $sp^3$ with $0$ lone pairs,so it is tetrahedral.$3$. $SF_4$: Central atom $S$ has $6$ valence electrons. $H = (6+4)/2 = 5$. Hybridization is $sp^3d$ with $1$ lone pair. Due to the presence of a lone pair,its shape is see-saw,not tetrahedral.$4$. $SO_4^{2-}$: Central atom $S$ has $6$ valence electrons. $H = (6+0+2)/2 = 4$. Hybridization is $sp^3$ with $0$ lone pairs,so it is tetrahedral.Thus,$SF_4$ is the molecule that is not tetrahedral.

$I. SnCl_2$	$II. BeF_2$
$III. SO_2$	$IV. NO_2^+$
$V. C_2H_2$

Which of the following is $NOT$ tetrahedral in shape?

Similar Questions

Which of the following have linear structure?

$I. SnCl_2$ $II. BeF_2$

$III. SO_2$ $IV. NO_2^+$

$V. C_2H_2$

In the following reaction,how do the $Cl-P-Cl$ bond angles change?
$PCl_5 \longrightarrow PCl_4^+ + Cl^-$

In which of the following molecules are all bond lengths the same?

Which of the following species is non-linear?

What is the difference between $NO_2$ and $NO_2^-$? Explain.

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