The correct order of N compounds in their dec | vedclass

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Question

(A) To find the decreasing order of oxidation states,we calculate the oxidation state of nitrogen $(N)$ in each compound:$1$. In $HNO_{3}$: $1 + x + 3

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$HNO_{3}, NO, N_{2}, NH_{4}Cl$

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(A) To find the decreasing order of oxidation states,we calculate the oxidation state of nitrogen $(N)$ in each compound:$1$. In $HNO_{3}$: $1 + x + 3(-2) = 0 \implies x = +5$$2$. In $NO$: $x + (-2) = 0 \implies x = +2$$3$. In $N_{2}$: The oxidation state of an element in its free state is $0$.$4$. In $NH_{4}Cl$: $x + 4(1) + (-1) = 0 \implies x + 3 = 0 \implies x = -3$Comparing the values: $+5 > +2 > 0 > -3$.Therefore,the correct order is $HNO_{3} > NO > N_{2} > NH_{4}Cl$.

List $I$ (Compound)	List $II$ (Oxidation state of $N$)
$(A)$ $NO_2$	$(1)$ $+5$
$(B)$ $HNO$	$(2)$ $-3$
$(C)$ $NH_3$	$(3)$ $+4$
$(D)$ $N_2O_5$	$(4)$ $+1$

Column-$I$	Column-$II$
$A$. Positively charged ion	$1$. $+7$
$B$. Oxidation number of all neutral atoms	$2$. $-1$
$C$. Oxidation number of hydrogen $(H^+)$	$3$. $+1$
$D$. Oxidation number of fluorine in $NaF$	$4$. $0$
$E$. Negatively charged ion	$5$. Cation
	$6$. Anion

The correct order of $N$ compounds in their decreasing order of oxidation states is:

Similar Questions

Match List $I$ with List $II$ and select the correct answer using the codes given below the lists:
List $I$ (Compound) List $II$ (Oxidation state of $N$)
$(A)$ $NO_2$ $(1)$ $+5$
$(B)$ $HNO$ $(2)$ $-3$
$(C)$ $NH_3$ $(3)$ $+4$
$(D)$ $N_2O_5$ $(4)$ $+1$

Codes: $A \quad B \quad C \quad D$

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